To find the work done (A) in this scenario, we can use the formula:
A = mgh + 0.5mv^2
where:m = mass = 3 kgg = acceleration due to gravity = 10 m/s^2h = height = 1 ma = acceleration = 2 m/s^2
First, let's calculate the potential energy (mgh):
Potential energy (mgh) = 3 kg 10 m/s^2 1 m = 30 J
Next, let's calculate the kinetic energy (0.5mv^2):
v = u + atv = 0 + 2 m/s^2 * 1 s = 2 m/s
Kinetic energy (0.5mv^2) = 0.5 3 kg (2 m/s)^2 = 6 J
Finally, we can find the total work done (A):
A = 30 J + 6 J = 36 J
Therefore, the total work done in this scenario is 36 Joules.
To find the work done (A) in this scenario, we can use the formula:
A = mgh + 0.5mv^2
where:
m = mass = 3 kg
g = acceleration due to gravity = 10 m/s^2
h = height = 1 m
a = acceleration = 2 m/s^2
First, let's calculate the potential energy (mgh):
Potential energy (mgh) = 3 kg 10 m/s^2 1 m = 30 J
Next, let's calculate the kinetic energy (0.5mv^2):
v = u + at
v = 0 + 2 m/s^2 * 1 s = 2 m/s
Kinetic energy (0.5mv^2) = 0.5 3 kg (2 m/s)^2 = 6 J
Finally, we can find the total work done (A):
A = 30 J + 6 J = 36 J
Therefore, the total work done in this scenario is 36 Joules.