V0=20 м/с
V1=0 м/c
g=10
t-?

Предыдущий
вопрос Следующий
вопрос

To find the time (t) it takes for the object to come to a stop (V1=0 m/s) when decelerating at a constant rate due to gravity, we can use the following kinematic equation:

V1 = V0 + gt

0 = 20 + 10t

Solving for t:

10t = -20

t = -20/10

t = -2 seconds

Therefore, it will take 2 seconds for the object to come to a stop after decelerating at a constant rate due to gravity.