To find the values of x, v, and s after 2 seconds, we can substitute t=2 into the equation x=4-3t.

x=4-3(2)
x=4-6
x=-2

Therefore, x= -2 after 2 seconds.

To find v, we can differentiate the equation x=4-3t with respect to t.

v=dx/dt=-3

Therefore, v=-3 after 2 seconds.

To find s, we need to integrate v= -3 with respect to t.

s=∫v dt = ∫(-3) dt = -3t + C

To find the constant term C, we can use the initial condition x(0) = x0.

x0 = 4 - 3(0) = 4

Therefore, when t=0, x=4. Substituting this into the equation we get:

4 = -3(0) + C
C=4

So, s=-3t + 4

After 2 seconds:

s=-3(2) + 4
s=-6 + 4
s=-2

Therefore, the values of x, v, and s after 2 seconds are:

x = -2
v = -3
s = -2