To determine the final velocity (V2), we can use the principle of conservation of energy. The initial kinetic energy (KE1) is equal to the final potential energy (PE2) plus the final kinetic energy (KE2).

KE1 = PE2 + KE2

The initial kinetic energy is zero (V1 = 0 m/s), and the total energy at the initial height (E1) is all in the form of potential energy:

E1 = PE1 = mgh1,
where m is the mass of the object (which we don't need for this calculation).

At the final height (h2), the total energy (E2) of the object is in the form of potential energy (PE2) and kinetic energy (KE2):

E2 = PE2 + KE2 = mgh2 + 0.5mv^2.

Since energy is conserved, we can equate the two expressions for energy:

PE1 = PE2 + KE2
mgh1 = mgh2 + 0.5mv^2,

Then, solve for the final velocity (V2):

0.5mv^2 = mgh1 - mgh2
v^2 = 2gh1 - 2gh2
v = √(2gh1 - 2gh2).

Substitute the values for h1 (6m) and h2 (1.5m) into the equation:

v = √(2 9.81 6 - 2 9.81 1.5)
v = √(117.72 - 29.43)
v = √88.29
v ≈ 9.39 m/s.

Therefore, the final velocity (V2) is approximately 9.39 m/s.