Given that cos A = 5/6, we can find sin A using the fact that cos^2A + sin^2A = 1.
sin^2A = 1 - cos^2Asin^2A = 1 - (5/6)^2sin^2A = 1 - 25/36sin^2A = 11/36sin A = √(11)/6
To find tan A, we can use the identity tan A = sin A / cos A.
tan A = sin A / cos Atan A = (√11/6) / (5/6)tan A = √11 / 5
Therefore, sin A = √11/6 and tan A = √11/5.
Given that cos A = 5/6, we can find sin A using the fact that cos^2A + sin^2A = 1.
sin^2A = 1 - cos^2A
sin^2A = 1 - (5/6)^2
sin^2A = 1 - 25/36
sin^2A = 11/36
sin A = √(11)/6
To find tan A, we can use the identity tan A = sin A / cos A.
tan A = sin A / cos A
tan A = (√11/6) / (5/6)
tan A = √11 / 5
Therefore, sin A = √11/6 and tan A = √11/5.