Molar mass of Al2O3 = (2 x molar mass of Al) + (3 x molar mass of O) Molar mass of Al = 26.98 g/mol Molar mass of O = 16.00 g/mol
Molar mass of Al2O3 = (2 x 26.98) + (3 x 16.00) = 54.28 + 48 = 102.28 g/mol
Mass of 0.5 moles of Al2O3 = 0.5 moles x 102.28 g/mol = 51.14 g
Number of particles in 0.5 moles of Al2O3 = 0.5 moles x 6.022 x 10^23 particles/mole = 3.011 x 10^23 particles
Therefore, the molar mass of Al2O3 is 102.28 g/mol, the mass of 0.5 moles of Al2O3 is 51.14 g, and the number of particles in 0.5 moles of Al2O3 is 3.011 x 10^23 particles.
Molar mass of Al2O3 = (2 x molar mass of Al) + (3 x molar mass of O)
Molar mass of Al = 26.98 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of Al2O3 = (2 x 26.98) + (3 x 16.00) = 54.28 + 48 = 102.28 g/mol
Mass of 0.5 moles of Al2O3 = 0.5 moles x 102.28 g/mol = 51.14 g
Number of particles in 0.5 moles of Al2O3 = 0.5 moles x 6.022 x 10^23 particles/mole = 3.011 x 10^23 particles
Therefore, the molar mass of Al2O3 is 102.28 g/mol, the mass of 0.5 moles of Al2O3 is 51.14 g, and the number of particles in 0.5 moles of Al2O3 is 3.011 x 10^23 particles.