CuO->Cu->CuCI2->Cu(OH)2->CuSO4

Предыдущий
вопрос Следующий
вопрос

The given sequence represents the reduction of copper oxide (CuO) to copper sulfate (CuSO4) through various chemical reactions:

CuO is reduced to Cu (copper) by losing oxygen.Cu is then treated with hydrochloric acid (HCl) to form copper chloride (CuCl2).Copper chloride is further reacted with sodium hydroxide (NaOH) to produce copper hydroxide (Cu(OH)2).Finally, copper hydroxide is reacted with sulfuric acid (H2SO4) to yield copper sulfate (CuSO4).

This sequence demonstrates the stepwise reduction and modification of copper compounds to ultimately obtain copper sulfate.