m(C)=3.6g алюминийдин артык молшеримен арекеттескенде тузилген алюминий карбидинин (Al4C3) массасы

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вопрос

Aluminium reacts with carbon to form aluminium carbide (Al4C3) according to the following balanced chemical equation:

4 Al + 3 C -----> Al4C3

From the equation, we can see that 4 moles of Al react with 3 moles of C to form 1 mole of Al4C3.

Given that the mass of Al (m) is 3.6g, we first need to calculate the molar mass of aluminium (Al) and aluminium carbide (Al4C3).

The molar mass of Al is 26.98 g/mol
The molar mass of Al4C3 is 144.96 g/mol

Next, we calculate the number of moles of Al in 3.6g:

Number of moles = Mass / Molar mass
Number of moles of Al = 3.6g / 26.98 g/mol = 0.1332 mol

Using the mole ratio in the balanced equation, we find that the number of moles of Al4C3 formed is:

Number of moles of Al4C3 = Number of moles of Al / 4 = 0.1332 mol / 4 = 0.0333 mol

Finally, we calculate the mass of Al4C3 formed:

Mass = Number of moles x Molar mass
Mass of Al4C3 = 0.0333 mol x 144.96 g/mol = 4.83g

Therefore, when 3.6g of aluminium reacts with carbon to form aluminium carbide (Al4C3), the mass of the Al4C3 formed is 4.83g.