1) Mr(Al(OH)3) = Ar(Al) + 3*(Ar(O) + Ar(H)) = 27 + 3*(16+1) = 78
ω(O) = (3*Ar(O)/Mr(Al(OH)3))*100% = (3*16/78)*100% ≈ 61,54%
2) Mr(KOH) = Ar(K) + Ar(O) + Ar(H) = 39 + 16 + 1 = 56
ω(O) = (Ar(O)/Mr(KOH))*100% = (16/56)*100% ≈ 28,57%
3) Mr(Ba(OH)2) = Ar(Ba) + 2*(Ar(O) + Ar(H)) = 137 + 2*(16+1) = 171
ω(O) = (2*Ar(O)/Mr(Ba(OH)2))*100% = (2*16/171)*100% ≈ 18,71%
1) Mr(Al(OH)3) = Ar(Al) + 3*(Ar(O) + Ar(H)) = 27 + 3*(16+1) = 78
ω(O) = (3*Ar(O)/Mr(Al(OH)3))*100% = (3*16/78)*100% ≈ 61,54%
2) Mr(KOH) = Ar(K) + Ar(O) + Ar(H) = 39 + 16 + 1 = 56
ω(O) = (Ar(O)/Mr(KOH))*100% = (16/56)*100% ≈ 28,57%
3) Mr(Ba(OH)2) = Ar(Ba) + 2*(Ar(O) + Ar(H)) = 137 + 2*(16+1) = 171
ω(O) = (2*Ar(O)/Mr(Ba(OH)2))*100% = (2*16/171)*100% ≈ 18,71%