(NH4)3PO4
Mr((NH4)3PO4) = 3*(Ar(N)+4*Ar(H)) + Ar(P) + 4*Ar(O) = 3*(14+4*1) + 31 + 4*16 = 149
ω(N) = (3*Ar(N)/Mr((NH4)3PO4))*100% = (3*14/149)*100% ≈ 28,19%
ω(H) = (3*4*Ar(H)/Mr((NH4)3PO4))*100% = (3*4*1/149)*100% ≈ 8,05%
ω(P) = (Ar(P)/Mr((NH4)3PO4))*100% = (31/149)*100% ≈ 20,81%
ω(O) = (4*Ar(O)/Mr((NH4)3PO4))*100% = (4*16/149)*100% ≈ 42,95%
Ответ: ω(N) = 28,19%, ω(H) = 8,05%, ω(P) = 20,81%, ω(O) = 42,95%
(NH4)3PO4
Mr((NH4)3PO4) = 3*(Ar(N)+4*Ar(H)) + Ar(P) + 4*Ar(O) = 3*(14+4*1) + 31 + 4*16 = 149
ω(N) = (3*Ar(N)/Mr((NH4)3PO4))*100% = (3*14/149)*100% ≈ 28,19%
ω(H) = (3*4*Ar(H)/Mr((NH4)3PO4))*100% = (3*4*1/149)*100% ≈ 8,05%
ω(P) = (Ar(P)/Mr((NH4)3PO4))*100% = (31/149)*100% ≈ 20,81%
ω(O) = (4*Ar(O)/Mr((NH4)3PO4))*100% = (4*16/149)*100% ≈ 42,95%
Ответ: ω(N) = 28,19%, ω(H) = 8,05%, ω(P) = 20,81%, ω(O) = 42,95%