Mr(FeO) = Ar(Fe) + Ar(O) = 56 + 16 = 72
w(Fe) = (Ar(Fe)/Mr(FeO))*100% = (56/72)*100% ≈ 77,78%
w(O) = 100% - w(Fe) = 100% - 77,78% = 22,22%
Ответ: w(Fe) = 77,78%, w(O) = 22,22%
Mr(FeO) = Ar(Fe) + Ar(O) = 56 + 16 = 72
w(Fe) = (Ar(Fe)/Mr(FeO))*100% = (56/72)*100% ≈ 77,78%
w(O) = 100% - w(Fe) = 100% - 77,78% = 22,22%
Ответ: w(Fe) = 77,78%, w(O) = 22,22%