При распаде молекулы оксида ртути образуется 4 грамм кислорода и 50.2 г ртути Найдите массу исходного оксида ртути.

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Molar mass of mercury (Hg): 200.59 g/mol
Molar mass of oxygen (O): 16 g/mol

Given:
Mass of oxygen formed = 4 g
Mass of mercury formed = 50.2 g

Let the mass of the original mercury oxide be x g.

From the given information, we can set up the following equations:

4 g (O)/16 g/mol = 0.25 mol O
50.2 g (Hg)/200.59 g/mol = 0.25 mol Hg

Since the formula of mercury oxide is HgO, the molar ratio of Hg to O in HgO is 1:1.

So, the molar mass of HgO = Molar mass of Hg + Molar mass of O
Molar mass of HgO = 200.59 g/mol + 16 g/mol = 216.59 g/mol

Now, we can find the molar mass of the original mercury oxide:
0.25 mol HgO * 216.59 g/mol = 54.1475 g

Therefore, the mass of the original mercury oxide was 54.1475 grams.