N(SO2) = 54 * 10^23
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m-?
V-?

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вопрос

To find the mass (m) and volume (V) of the given number of molecules of SO2, we need to know the molar mass of SO2 and use Avogadro's number.

Calculate the molar mass of SO2:
Sulfur (S) has a molar mass of approximately 32 g/mol.
Oxygen (O) has a molar mass of approximately 16 g/mol (there are 2 oxygen atoms in SO2).

Molar mass of SO2 = (1 32 g/mol) + (2 16 g/mol)
Molar mass of SO2 = 32 g/mol + 32 g/mol
Molar mass of SO2 = 64 g/mol

Calculate the mass (m):
1 mole of SO2 contains 6.022 × 10^23 molecules.
Therefore, 1 molecule of SO2 has a mass of: 64 g / 6.022 × 10^23 molecules ≈ 1.06095 × 10^-22 g

To find the mass of 54 10^23 molecules, multiply this by the given number:
m = (54 10^23) * 1.06095 × 10^-22 g = 5.73277 g

So, the mass of 54 * 10^23 molecules of SO2 is approximately 5.73277 grams.

Calculate the volume (V):
Given that SO2 is a gas, we can use the ideal gas law, PV = nRT, to find the volume.

Since we're given the number of molecules and not moles, we need to convert the number of molecules to moles using Avogadro's number:
54 10^23 SO2 molecules (1 mol / 6.022 × 10^23 molecules) = 0.89658 moles

Now, we can calculate the volume at STP (standard temperature and pressure):
STP conditions are 273 K and 1 atm, so R = 0.0821 L.atm/mol.K

V = (0.89658 moles) (0.0821 L.atm/mol.K) (273 K) / (1 atm)
V = 21.53 L

Therefore, the volume of 54 * 10^23 molecules of SO2 at STP is approximately 21.53 liters.