CH4-C2H2-C2H4-C2H5OH-C2H5Br-C2H4

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вопрос

The reactions involved in the formation of these molecules are as follows:

CH4 (methane) → C2H2 (acetylene) + 2H
This reaction involves the pyrolysis of methane to form acetylene and hydrogen gas.

C2H2 (acetylene) → C2H4 (ethylene
This reaction involves the hydrogenation of acetylene to form ethylene.

C2H4 (ethylene) + H2O → C2H5OH (ethanol
This reaction involves the hydration of ethylene to form ethanol.

C2H5OH (ethanol) + HBr → C2H5Br (ethyl bromide) + H2
This reaction involves the substitution of the hydroxyl group in ethanol with a bromine atom to form ethyl bromide.