W(c)=83,7%
D(O2)=2,69
найти:
CxHy

Предыдущий
вопрос Следующий
вопрос

To determine the formula for the hydrocarbon CxHy, we can start by calculating the percentage composition of carbon and hydrogen in the compound using the given data.

Given:
W(C) = 83.7%
D(O2) = 2.69

Step 1: Calculate the percentage of oxygen in the compound

%O = 100% - %C = 100% - 83.7% = 16.3%

Step 2: Calculate the moles of carbon, hydrogen, and oxygen in the compound

Let the moles of C = x
Moles of O = 2.69/32 [Molar mass of oxygen] = 0.084 moles

Since the compound is a hydrocarbon,
Moles of H = x*2

Step 3: Convert moles to mass
Mass of C = x12 [molar mass of carbon]
Mass of H = 2x1 [molar mass of hydrogen]
Mass of O = 0.084*16 [molar mass of oxygen]

Step 4: Calculate the mass percentages of C, H, and O in the compound
%C = (Mass of C / Total mass of compound) 100
%C = (12x / (12x + 2x + 0.08416)) 100
%C = (12x / (14x + 1.344)) 100

%H = (Mass of H / Total mass of compound) 100
%H = (21 / (12x + 2x + 0.08416)) 100
%H = (2 / (14x + 1.344)) * 100

%O = (Mass of O / Total mass of compound) 100
%O = (0.08416 / (12x + 2x + 0.08416)) 100
%O = (1.344 / (14x + 1.344)) * 100

Step 5: Set up the equations based on the given data

%C = 83.7% => (12x / (14x + 1.344)) 100 = 83.7
%H = => (2 / (14x + 1.344)) 100 = ?
%O = 16.3% => (1.344 / (14x + 1.344)) * 100 = 16.3

Step 6: Solve for x

From the equation:
(12x / (14x + 1.344)) * 100 = 83.7
12x = 83.7(14x + 1.344)

This equation can be solved to find the value of x, which will give us the subscripts for C and H in the compound CxHy.