In this reaction, sodium chloride (NaCl) reacts with chlorine gas (Cl2) in the presence of copper (II) chloride (CuCl2) and water (H2O) to form copper (II) hydroxide (Cu(OH)2), copper (II) oxide (CuO2), and additional copper (II) chloride (CuCl2) and sodium chloride (NaCl).
The reaction you have provided involves the following chemicals:
NaCl (Sodium Chloride)Cl2 (Chlorine gas)CuCl2 (Copper (II) Chloride)Cu(OH)2 (Copper (II) Hydroxide)CuO2 (Copper (II) Oxide)The overall reaction would be:
2 NaCl + Cl2 + 2 CuCl2 + 2 H2O -> 2 Cu(OH)2 + CuO2 + 2 CuCl2 + 2 NaCl
In this reaction, sodium chloride (NaCl) reacts with chlorine gas (Cl2) in the presence of copper (II) chloride (CuCl2) and water (H2O) to form copper (II) hydroxide (Cu(OH)2), copper (II) oxide (CuO2), and additional copper (II) chloride (CuCl2) and sodium chloride (NaCl).