m(Ca(OH)2 )= 148 г.р-ра W (Ca(OH)2)=10% m ( осадка)-?

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вопрос

We can start by calculating the amount of Ca(OH)2 in the solution:

10% of the total mass is Ca(OH)2
m(Ca(OH)2) = 148 г.
So, 10% of the total mass is Ca(OH)2:
0.1 m(total) = m(Ca(OH)2)
0.1 m(total) = 148 г.
m(total) = 148 г / 0.1
m(total) = 1480 г

Now we can calculate the mass of the precipitate (m(осадка)) which is the difference between the total mass and the mass of Ca(OH)2:
m(осадка) = m(total) - m(Ca(OH)2)
m(осадка) = 1480 г - 148 г
m(осадка) = 1332 г

Therefore, the mass of the precipitate is 1332 grams.