M(Cl2)=300г V (Cl2)-?

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вопрос

To calculate the volume of chlorine gas (Cl2) produced from 300g of chlorine gas, we need to use the molar mass of Cl2 and the ideal gas law.

Calculate the molar mass of Cl2:
Molar mass of Cl = 35.45 g/mol
Molar mass of Cl2 = 2(35.45) = 70.90 g/mol

Calculate the number of moles of Cl2:
Number of moles = Mass / Molar mass
Number of moles = 300g / 70.90 g/mol = 4.22 moles

Use the ideal gas law to calculate the volume of Cl2:
PV = nRT
V = nRT / P

Given:
n = 4.22 moles
R = 0.0821 L·atm/(K·mol) (ideal gas constant)
T = temperature (assumed to be 298 K for room temperature)
P = pressure (assumed to be 1 atm for standard pressure)

V = 4.22 moles x 0.0821 L·atm/(K·mol) x 298 K / 1 atm
V = 104.7 L

Therefore, the volume of chlorine gas produced from 300g of Cl2 is approximately 104.7 liters.