To find the molarity of NH3, we first need to calculate the number of moles of NH3 present.
The balanced equation for the reaction is: NH3 -> N + 3H
From the balanced equation, we can see that 1 mole of NH3 produces 1 mole of N and 3 moles of H.
Given that there are 2.5 moles of NH3 present, we can calculate the moles of N and H produced: Moles of N = 2.5 moles Moles of H = 2.5 moles * 3 = 7.5 moles
Now, we can calculate the total moles of NH3 and the total volume in liters to find the molarity:
Total moles of NH3 = 2.5 moles Total volume in liters = ?
Given in the problem is that the volume is not given, so we cannot calculate the molarity without knowing the volume of the solution.
To find the molarity of NH3, we first need to calculate the number of moles of NH3 present.
The balanced equation for the reaction is:
NH3 -> N + 3H
From the balanced equation, we can see that 1 mole of NH3 produces 1 mole of N and 3 moles of H.
Given that there are 2.5 moles of NH3 present, we can calculate the moles of N and H produced:
Moles of N = 2.5 moles
Moles of H = 2.5 moles * 3 = 7.5 moles
Now, we can calculate the total moles of NH3 and the total volume in liters to find the molarity:
Total moles of NH3 = 2.5 moles
Total volume in liters = ?
Given in the problem is that the volume is not given, so we cannot calculate the molarity without knowing the volume of the solution.