Mr(ROH)=40
Mr (R2O)=72
Mr(RO)=153
Mr (R|OH|3)=103

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вопрос

To determine the molar mass of the compound ROH, we will first need to break down the molar masses of the individual elements:

Molar mass of R = Mr(RO) - Mr(O) = 153 - 16 = 137
Molar mass of O = Mr(RO) - Mr(R) = 153 - 137 = 16
Molar mass of H = Mr(ROH) - Mr(R) - Mr(O) = 40 - 137 - 16 = -113

Therefore, the molar mass of the compound ROH is 137 + 16 + 40 = 193 g/mol.