M(розч)=200
w1(C12H22O11)=20
m2(розч)=100
w2(C12H22011)=5
w3 (C12H22011)-?

Предыдущий
вопрос Следующий
вопрос

To find the mass of C12H22O11 in the final solution, we can use the principle of conservation of mass:

m1(розч) = m2(розч) + m(C12H22O11
200g = 100g + m(C12H22O11
m(C12H22O11) = 200g - 100
m(C12H22O11) = 100g

Now, we can calculate the final weight percent of C12H22O11 in the solution:

w3(C12H22O11) = (m(C12H22O11) / m2(розч)) 100
w3(C12H22O11) = (100g / 100g) 100
w3(C12H22O11) = 100%

Therefore, the final weight percent of C12H22O11 in the solution is 100%.