KI + KIO3 + H2SO4= I2+K2SO4+
H2O

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вопрос

This is a redox reaction in which potassium iodide (KI) and potassium iodate (KIO3) react with sulfuric acid (H2SO4) to form elemental iodine (I2), potassium sulfate (K2SO4), and water (H2O).

The balanced chemical equation for this reaction is:

2KI + KIO3 + 5H2SO4 → 3I2 + K2SO4 + 4H2O

So, the products of this reaction are elemental iodine (I2), potassium sulfate (K2SO4), and water (H2O).