ZnO=81г.
HBr=81г.
ZnBr2=?

Предыдущий
вопрос Следующий
вопрос

To find the molar mass of ZnBr2, we first need to determine the molar mass of each element in the compound.

The molar mass of Zinc (Zn) = 65.38 g/mol
The molar mass of Bromine (Br) = 79.90 g/mol

Now, we can calculate the molar mass of ZnBr2:
Molar mass of ZnBr2 = 2(molar mass of Br) + molar mass of Zn
Molar mass of ZnBr2 = 2(79.90 g/mol) + 65.38 g/mol
Molar mass of ZnBr2 = 159.80 g/mol + 65.38 g/mol
Molar mass of ZnBr2 = 225.18 g/mol

Now, to find the mass of ZnBr2 in 81g of ZnBr2, we can use the formula:
Mass = Number of moles * Molar mass

Number of moles of ZnBr2 = mass / molar mass
Number of moles of ZnBr2 = 81g / 225.18 g/mol
Number of moles of ZnBr2 = 0.36 mol

Now, we can find the mass of ZnBr2 in 0.36 mol:
Mass = 0.36 mol * 225.18 g/mol
Mass = 81.06 g

Therefore, the mass of ZnBr2 in 81g of ZnBr2 is 81.06g.