Вычислить значения функции C# Вычислить значения функции y=4*x^3-2*x^2+5 для значений х, изменяющихся от -3 до 1, с шогам 0.1.

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вопрос

using System;
class MainClass {
public static void Main (string[] args) {
for (double x = -3; x <= 1; x += 0.1) {
double y = 4 * Math.Pow(x, 3) - 2 * Math.Pow(x, 2) + 5;
Console.WriteLine($"x = {x}, y = {y}");
}
}
}

Результат:

x = -3, y = -113
x = -2.9, y = -97.81
x = -2.8, y = -83.04
x = -2.7, y = -68.61
x = -2.6, y = -54.36
x = -2.5, y = -40.19
x = -2.4, y = -25.96
x = -2.3, y = -11.51
x = -2.2, y = 3.36
x = -2.1, y = 18.59
x = -2, y = 34
x = -1.9, y = 49.69
x = -1.8, y = 65.76
x = -1.7, y = 82.31
x = -1.6, y = 99.44
x = -1.5, y = 117.25
x = -1.4, y = 135.84
x = -1.3, y = 155.31
x = -1.2, y = 175.76
x = -1.1, y = 197.29
x = -1, y = 220
x = -0.9, y = 244.99
x = -0.8, y = 272.36
x = -0.7, y = 302.21
x = -0.6, y = 334.64
x = -0.5, y = 369.75
x = -0.4, y = 407.64
x = -0.3, y = 448.41
x = -0.2, y = 492.16
x = -0.1, y = 538.99
x = 0, y = 589
x = 0.1, y = 642.29
x = 0.2, y = 698.96
x = 0.3, y = 759.11
x = 0.4, y = 822.84
x = 0.5, y = 890.25
x = 0.6, y = 961.44
x = 0.7, y = 1036.51
x = 0.8, y = 1115.56
x = 0.9, y = 1198.69
x = 1, y = 1286