На отрезке [1;2] с шагом 0,1 протабулировать функцию: cos2/x-2sin1/x+1/x

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Подставим каждое из значений x с шагом 0,1 в функцию и вычислим результат:

При x = 1:
cos(2/1) - 2sin(1/1) + 1/1 = cos(2) - 2sin(1) + 1 = -0.239

При x = 1.1:
cos(2/1.1) - 2sin(1/1.1) + 1/1.1 = cos(1.818) - 2sin(0.909) + 0.909 = -0.066

При x = 1.2:
cos(2/1.2) - 2sin(1/1.2) + 1/1.2 = cos(1.667) - 2sin(0.833) + 0.833 = 0.228

При x = 1.3:
cos(2/1.3) - 2sin(1/1.3) + 1/1.3 = cos(1.538) - 2sin(0.769) + 0.769 = 0.460

При x = 1.4:
cos(2/1.4) - 2sin(1/1.4) + 1/1.4 = cos(1.429) - 2sin(0.714) + 0.714 = 0.616

При x = 1.5:
cos(2/1.5) - 2sin(1/1.5) + 1/1.5 = cos(1.333) - 2sin(0.667) + 0.667 = 0.730

При x = 1.6:
cos(2/1.6) - 2sin(1/1.6) + 1/1.6 = cos(1.25) - 2sin(0.625) + 0.625 = 0.821

При x = 1.7:
cos(2/1.7) - 2sin(1/1.7) + 1/1.7 = cos(1.176) - 2sin(0.588) + 0.588 = 0.899

При x = 1.8:
cos(2/1.8) - 2sin(1/1.8) + 1/1.8 = cos(1.111) - 2sin(0.556) + 0.556 = 0.969

При x = 1.9:
cos(2/1.9) - 2sin(1/1.9) + 1/1.9 = cos(1.053) - 2sin(0.526) + 0.526 = 1.034

При x = 2:
cos(2/2) - 2sin(1/2) + 1/2 = cos(1) - 2sin(0.5) + 0.5 = 1.079

Таким образом, протабулировав функцию на отрезке [1;2] с шагом 0,1 получаем:
x = 1.0; f(x) = -0.239
x = 1.1; f(x) = -0.066
x = 1.2; f(x) = 0.228
x = 1.3; f(x) = 0.460
x = 1.4; f(x) = 0.616
x = 1.5; f(x) = 0.730
x = 1.6; f(x) = 0.821
x = 1.7; f(x) = 0.899
x = 1.8; f(x) = 0.969
x = 1.9; f(x) = 1.034
x = 2.0; f(x) = 1.079