Var sum,a,num:integer begin sum:= 0; num:=0; readln(a); while a<>do begin sum:=sum+a if (a mod 2=0) and (a mod 5=0) then num:= num+1 readln (a) end; writelh (sum), writelh (num) end.
The given code is a pseudo code snippet for a program that calculates the sum of numbers entered by the user and counts how many of those numbers are divisible by both 2 and 5.
Here's a breakdown of the code:
Initialize variables sum, a, and num as integers.Set sum and num to 0.Read the value of a from the user.Start a while loop that continues as long as a is not equal to 0.Within the loop: Add the value of a to sum.Check if a is divisible by both 2 and 5. If it is, increment num by 1.Read the next value of a from the user.Print the final value of sum and num.
However, there are a couple of issues in the code:
The condition while a<> is not complete. It should be while a<>0.There is a syntax error in the line if (a mod 2=0) and (a mod 5=0) then num:= num+1 as it is missing the begin and end keywords to define the block of code to be executed.
Here is the corrected version of the code:
Var sum, a, num: integer; begin sum := 0; num := 0; readln(a); while a<>0 do begin sum := sum + a; if (a mod 2 = 0) and (a mod 5 = 0) then num := num + 1; readln(a); end; writeln(sum); writeln(num); end.
This code will now correctly calculate the sum of numbers entered by the user and count the numbers that are divisible by both 2 and 5.
The given code is a pseudo code snippet for a program that calculates the sum of numbers entered by the user and counts how many of those numbers are divisible by both 2 and 5.
Here's a breakdown of the code:
Initialize variables sum, a, and num as integers.Set sum and num to 0.Read the value of a from the user.Start a while loop that continues as long as a is not equal to 0.Within the loop:Add the value of a to sum.Check if a is divisible by both 2 and 5. If it is, increment num by 1.Read the next value of a from the user.Print the final value of sum and num.
However, there are a couple of issues in the code:
The condition while a<> is not complete. It should be while a<>0.There is a syntax error in the line if (a mod 2=0) and (a mod 5=0) then num:= num+1 as it is missing the begin and end keywords to define the block of code to be executed.Here is the corrected version of the code:
Var sum, a, num: integer;begin
sum := 0;
num := 0;
readln(a);
while a<>0 do
begin
sum := sum + a;
if (a mod 2 = 0) and (a mod 5 = 0) then
num := num + 1;
readln(a);
end;
writeln(sum);
writeln(num);
end.
This code will now correctly calculate the sum of numbers entered by the user and count the numbers that are divisible by both 2 and 5.