Var sum,a,num:integer begin
sum:= 0; num:=0; readln(a);
while a<>do begin
sum:=sum+a
if (a mod 2=0) and (a mod 5=0)
then num:= num+1
readln (a)
end;
writelh (sum), writelh (num)
end.

23 Дек 2019 в 19:55
230 +1
0
Ответы
1

The given code is a pseudo code snippet for a program that calculates the sum of numbers entered by the user and counts how many of those numbers are divisible by both 2 and 5.

Here's a breakdown of the code:

Initialize variables sum, a, and num as integers.Set sum and num to 0.Read the value of a from the user.Start a while loop that continues as long as a is not equal to 0.Within the loop:
Add the value of a to sum.Check if a is divisible by both 2 and 5. If it is, increment num by 1.Read the next value of a from the user.Print the final value of sum and num.

However, there are a couple of issues in the code:

The condition while a<> is not complete. It should be while a<>0.There is a syntax error in the line if (a mod 2=0) and (a mod 5=0) then num:= num+1 as it is missing the begin and end keywords to define the block of code to be executed.

Here is the corrected version of the code:

Var sum, a, num: integer;
begin
sum := 0;
num := 0;
readln(a);
while a<>0 do
begin
sum := sum + a;
if (a mod 2 = 0) and (a mod 5 = 0) then
num := num + 1;
readln(a);
end;
writeln(sum);
writeln(num);
end.

This code will now correctly calculate the sum of numbers entered by the user and count the numbers that are divisible by both 2 and 5.

18 Апр 2024 в 23:09
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