ABB+bcc+caa=1887 olarsa a+b+c tap

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вопрос

First, let's represent the given equation in terms of a single variable:

a + b + c + b + c + c + a + a = 188
2a + 2b + 3c = 1887

Now, we'll divide the equation by 2:

a + b + 3c/2 = 943.5

From this equation, we can see that a, b, and c are integers, and we need to find their values which satisfy the equation a + b + 3c/2 = 943.5.

Since a, b, and c are integers, the only solution to this equation is when c = 2. Therefore, substituting c = 2 back into the equation, we get:

a + b + 3(2)/2 = 943.
a + b + 3 = 943.
a + b = 940.5

Since a and b are two different integers that sum up to 940.5, the only solution is a = 470 and b = 470.

Therefore, a + b + c = 470 + 470 + 2 = 942.

Therefore, a + b + c = 942.