(x-3)^2 - 5 = x(x+2)
Expanding the left side(x-3)(x-3) - = x^2 - 3x - 3x + 9 - = x^2 - 6x + 4
Setting the equation equal to the right sidex(x+2= x^2 + 2x
Now equate the two sidesx^2 - 6x + 4 = x^2 + 2x
Subtract x^2 from both sides-6x + 4 = 2x
Add 6x to both sides4 = 8x
Divide by 8x = 0.5
Therefore, the solution to the equation is x = 0.5.
(x-3)^2 - 5 = x(x+2)
Expanding the left side
(x-3)(x-3) -
= x^2 - 3x - 3x + 9 -
= x^2 - 6x + 4
Setting the equation equal to the right side
x(x+2
= x^2 + 2x
Now equate the two sides
x^2 - 6x + 4 = x^2 + 2x
Subtract x^2 from both sides
-6x + 4 = 2x
Add 6x to both sides
4 = 8x
Divide by 8
x = 0.5
Therefore, the solution to the equation is x = 0.5.