{5−5(0,2v−2x)=3(3x+2)+2v{4(x−5v)−(2x+v)=10−2(2x+v)

Предыдущий
вопрос Следующий
вопрос

To solve this system of equations, we will start by simplifying each equation one by one.

5 - 5(0.2v - 2x) = 3(3x + 2) + 2v
5 - 1 + 10v = 9x + 6 + 2v
4 + 10v = 9x + 6 + 2v
10v - 2v = 9x + 6 - 4
8v = 9x + 2
v = (9/8)x + 1/4

4(x - 5v) - (2x + v) = 10 - 2(2x + v)
4x - 20v - 2x - v = 10 - 4x - 2v
2x - 21v = 10 - 4x - 2v
2x + 4x = 10 + 2v - 21v
6x = 10 - 19v
x = (10 - 19v) / 6

Now, we can substitute the expression for v from the first equation into the second equation and solve for x:

x = (10 - 19((9/8)x + 1/4)) / 6
x = (10 - (171/8)x - 19/4) / 6
6x = 60 - 171/8x - 19/4
48x = 480 - 171x - 38
48x + 171x = 480 - 38
219x = 442
x = 442 / 219
x = 82/41

Finally, substitute this value of x back into the equation for v:

v = (9/8)(82/41) + 1/4
v = 9/4 + 1/4
v = 10/4
v = 5/2

Therefore, the solution to the system of equations is x = 82/41 and v = 5/2.