To find the value of Y when x=2, we can plug in x=2 into the equation Y=4x^2+3x-5.
Y = 4(2)^2 + 3(2) - 5Y = 4(4) + 6 - 5Y = 16 + 6 - 5Y = 17
Therefore, when x=2, Y=17.
To find the value of Y when x=2, we can plug in x=2 into the equation Y=4x^2+3x-5.
Y = 4(2)^2 + 3(2) - 5
Y = 4(4) + 6 - 5
Y = 16 + 6 - 5
Y = 17
Therefore, when x=2, Y=17.