1.)(5х-1) (6х+2) (9х-3)=0 2.)(х-7) (6-х) (х-1/8)=0

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вопрос

Solving (5x-1)(6x+2)(9x-3) = 0:
Expanding the expression we get:
(5x-1)(6x+2)(9x-3) = 0
(30x^2 + 10x - 6x - 2)(9x-3)
(30x^2 + 4x - 3)(9x-3)
270x^3 + 36x^2 - 90x - 12x^2 + 24x - 9
270x^3 + 24x^2 - 66x - 9 = 0

Now, factor the expression:
9(30x^3 + 8x^2 - 22x - 3) = 0

Setting each factor to zero:
30x^3 + 8x^2 - 22x - 3 = 0
This is a polynomial equation that can be solved using various methods such as factoring, synthetic division, or graphing.

Solving (x-7)(6-x)(x-1/8) = 0:
Expanding the expression we get:
(x-7)(6-x)(x-1/8) = 0
(x^2 - x*6 - 7x + 42)(x-1/8)
(x^2 - 7x - 6x + 42)(x-1/8)
(x^2 - 13x + 42)(x-1/8)
x^3 - x^2/8 - 13x^2 + 13x + 336x - 42

Now, factor the expression:
8(x^3 - x^2 - 13x^2 + 13x + 336x - 42) = 0

Setting each factor to zero:
x^3 - x^2 - 13x^2 + 13x + 336x - 42 = 0
This is a polynomial equation that can be solved using various methods such as factoring, synthetic division, or graphing.