To divide (6x^3 + 19x^2 + 19x + 6) by (3x + 2), we perform polynomial long division.

2x^2 + 5x + 3
_____________________________
3x + 2 | 6x^3 + 19x^2 + 19x + 6
- (6x^3 + 4x^2)
___________________
15x^2 + 19x
- (15x^2 + 10x)
_______________
9x + 6
- (9x + 6)
___________
0

Therefore, the result of dividing (6x^3 + 19x^2 + 19x + 6) by (3x + 2) is 2x^2 + 5x + 3, with a remainder of 0.