To solve this equation, we can first simplify it by distributing the square root:
(1 - 2sin^2(x/2))(√(9-4x^2)) = 0
Next, we can set each factor equal to 0 and solve for x:
1 - 2sin^2(x/2) = 0
This means that x/2 can be:
x/2 = π/4 or x/2 = 3π/4 for sin(x/2) = 1/sqrt(2)x/2 = π/4 or x/2 = 3π/4 for sin(x/2) = -1/sqrt(2)
So the solutions for x are:
x = π/2, 3π/2, 5π/2, or 7π/2
To solve this equation, we can first simplify it by distributing the square root:
(1 - 2sin^2(x/2))(√(9-4x^2)) = 0
Next, we can set each factor equal to 0 and solve for x:
1 - 2sin^2(x/2) = 0
2sin^2(x/2) = -1sin^2(x/2) = 1/2
sin(x/2) = ±sqrt(1/2)
sin(x/2) = ±1/sqrt(2)
This means that x/2 can be:
x/2 = π/4 or x/2 = 3π/4 for sin(x/2) = 1/sqrt(2)
x/2 = π/4 or x/2 = 3π/4 for sin(x/2) = -1/sqrt(2)
So the solutions for x are:
x = π/2, 3π/2, 5π/2, or 7π/2