11y+y-5(3y- 2) = y-3(2+3y)

Предыдущий
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вопрос

Let's simplify each side of the equation separately.

Left side:
11y + y - 5(3y - 2)
11y + y - 15y + 10
-3y + 10

Right side:
y - 3(2 + 3y)
y - 6 - 9y
-8y - 6

Now, the equation becomes:
-3y + 10 = -8y - 6

Now we will solve for y.

Adding 8y to both sides:
-3y + 8y + 10 = -8y + 8y - 6
5y + 10 = -6

Subtracting 10 from both sides:
5y + 10 - 10 = -6 - 10
5y = -16

Dividing by 5:
y = -16/5

Therefore, the solution to the equation is y = -16/5.