To solve this system of equations using the method of addition, we need to first make one of the variables cancel out when the equations are added together.
Given the equations: 1) 3u - 5v = 20 2) u + v = 4
First, let's multiply the second equation by 5 to match the coefficients of v in both equations:
5(u + v) = 5(4) 5u + 5v = 20
Now, we can add this new equation to the first equation:
(3u - 5v) + (5u + 5v) = 20 + 20 8u = 40
Divide by 8 on both sides to solve for u:
u = 40 / 8 u = 5
Now that we have the value of u, we can substitute it back into one of the original equations to solve for v:
5 + v = 4 v = 4 - 5 v = -1
Therefore, the solution to the system of equations is u = 5 and v = -1.
To solve this system of equations using the method of addition, we need to first make one of the variables cancel out when the equations are added together.
Given the equations:
1) 3u - 5v = 20
2) u + v = 4
First, let's multiply the second equation by 5 to match the coefficients of v in both equations:
5(u + v) = 5(4)
5u + 5v = 20
Now, we can add this new equation to the first equation:
(3u - 5v) + (5u + 5v) = 20 + 20
8u = 40
Divide by 8 on both sides to solve for u:
u = 40 / 8
u = 5
Now that we have the value of u, we can substitute it back into one of the original equations to solve for v:
5 + v = 4
v = 4 - 5
v = -1
Therefore, the solution to the system of equations is u = 5 and v = -1.