Для каждого уравнения найдем уравнение вида y = kx + b:
x - 3y + 6 = 3y = x + y = (1/3)x + 2
x - 3y + 18 = 3y = x + 1y = (1/3)x + 6
3x + 3 = 2y - 2y = 3x + y = (3/2)x + (5/2)
x + 2 = 3y - 13y = x + 1y = (1/3)x + 6
Теперь построим графики этих функций на одном графике:
import matplotlib.pyplot as plimport numpy as np
x = np.linspace(-10, 10, 400y1 = (1/3)x + y2 = (1/3)x + y3 = (3/2)x + (5/2y4 = (1/3)x + 6
plt.figure(figsize=(10, 6)plt.plot(x, y1, label='y = (1/3)x + 2', color='red'plt.plot(x, y2, label='y = (1/3)x + 6', color='blue'plt.plot(x, y3, label='y = (3/2)x + (5/2)', color='green'plt.plot(x, y4, label='y = (1/3)x + 6', color='purple'plt.xlim(-10, 10plt.ylim(-10, 10plt.axhline(0, color='black',linewidth=0.5plt.axvline(0, color='black',linewidth=0.5plt.grid(color = 'gray', linestyle = '--', linewidth = 0.5plt.legend(plt.show()
Для каждого уравнения найдем уравнение вида y = kx + b:
x - 3y + 6 =
3y = x +
y = (1/3)x + 2
x - 3y + 18 =
3y = x + 1
y = (1/3)x + 6
3x + 3 = 2y -
2y = 3x +
y = (3/2)x + (5/2)
x + 2 = 3y - 1
3y = x + 1
y = (1/3)x + 6
Теперь построим графики этих функций на одном графике:
import matplotlib.pyplot as pl
import numpy as np
x = np.linspace(-10, 10, 400
y1 = (1/3)x +
y2 = (1/3)x +
y3 = (3/2)x + (5/2
y4 = (1/3)x + 6
plt.figure(figsize=(10, 6)
plt.plot(x, y1, label='y = (1/3)x + 2', color='red'
plt.plot(x, y2, label='y = (1/3)x + 6', color='blue'
plt.plot(x, y3, label='y = (3/2)x + (5/2)', color='green'
plt.plot(x, y4, label='y = (1/3)x + 6', color='purple'
plt.xlim(-10, 10
plt.ylim(-10, 10
plt.axhline(0, color='black',linewidth=0.5
plt.axvline(0, color='black',linewidth=0.5
plt.grid(color = 'gray', linestyle = '--', linewidth = 0.5
plt.legend(
plt.show()