To solve this system of equations, we can use the method of substitution or elimination.
Let's use the method of substitution.
First, solve the second equation for y2x - y = -y = 2x + 5
Now substitute y = 2x + 5 into the first equation5x + 3(2x + 5) = 5x + 6x + 15 = 11x + 15 = 11x = -1x = -1
Now that we have found the value of x, we can substitute it back into one of the original equations to find y2(-1) - y = --2 - y = -y = 3
Therefore, the solution to the system of equations is x = -1 and y = 3.
To solve this system of equations, we can use the method of substitution or elimination.
Let's use the method of substitution.
First, solve the second equation for y
2x - y = -
y = 2x + 5
Now substitute y = 2x + 5 into the first equation
5x + 3(2x + 5) =
5x + 6x + 15 =
11x + 15 =
11x = -1
x = -1
Now that we have found the value of x, we can substitute it back into one of the original equations to find y
2(-1) - y = -
-2 - y = -
y = 3
Therefore, the solution to the system of equations is x = -1 and y = 3.