To find the vertex of the function f(x) = 5x² - 12x + 5, we can use the formula for the x-coordinate of the vertex of a quadratic function:
x = -b/2a
In this case, the function is in the form f(x) = ax² + bx + c, so a = 5, b = -12, and c = 5. Plugging these values into the formula, we have:
x = -(-12) / 2(5x = 12 / 1x = 1.2
Now that we have found the x-coordinate of the vertex, we can plug this value back into the original function to find the y-coordinate:
f(1.2) = 5(1.2)² - 12(1.2) + f(1.2) = 5(1.44) - 14.4 + f(1.2) = 7.2 - 14.4 + f(1.2) = -2.2
Therefore, the vertex of the function f(x) = 5x² - 12x + 5 is (1.2, -2.2).
To find the vertex of the function f(x) = 5x² - 12x + 5, we can use the formula for the x-coordinate of the vertex of a quadratic function:
x = -b/2a
In this case, the function is in the form f(x) = ax² + bx + c, so a = 5, b = -12, and c = 5. Plugging these values into the formula, we have:
x = -(-12) / 2(5
x = 12 / 1
x = 1.2
Now that we have found the x-coordinate of the vertex, we can plug this value back into the original function to find the y-coordinate:
f(1.2) = 5(1.2)² - 12(1.2) +
f(1.2) = 5(1.44) - 14.4 +
f(1.2) = 7.2 - 14.4 +
f(1.2) = -2.2
Therefore, the vertex of the function f(x) = 5x² - 12x + 5 is (1.2, -2.2).