To solve the inequality x^2 - 4x + 1/(x - 3) < 2, we first need to rewrite it in a standard form:
x^2 - 4x + 1 < 2(x - 3)x^2 - 4x + 1 < 2x - 6x^2 - 6x + 7 < 0
Now we need to find the values of x that satisfy this inequality. To do that, we can factor the quadratic equation:
(x - 1)(x - 7) < 0
The solutions to this inequality are x < 1 and x > 7. Therefore, the values of x that satisfy x^2 - 4x + 1/(x - 3) < 2 are x < 1 and x > 7.
To solve the inequality x^2 - 4x + 1/(x - 3) < 2, we first need to rewrite it in a standard form:
x^2 - 4x + 1 < 2(x - 3)
x^2 - 4x + 1 < 2x - 6
x^2 - 6x + 7 < 0
Now we need to find the values of x that satisfy this inequality. To do that, we can factor the quadratic equation:
(x - 1)(x - 7) < 0
The solutions to this inequality are x < 1 and x > 7. Therefore, the values of x that satisfy x^2 - 4x + 1/(x - 3) < 2 are x < 1 and x > 7.