2х -3у = 1 х/у=0,75

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вопрос

To solve this system of equations, we can use substitution or elimination method.

Let's use substitution method:

First, isolate x in the second equation:
x = 0.75y

Now substitute x into the first equation:
2(0.75y) - 3y = 1
1.5y - 3y = 1
-1.5y = 1
y = -1/1.5
y = -2/3

Now that we have found the value of y, we can substitute it back into the second equation to find x:
x = 0.75(-2/3)
x = -1/2

Therefore, the solution to the system of equations is x = -1/2 and y = -2/3.