To solve this system of equations, we can use substitution or elimination method.
Let's use substitution method:
First, isolate x in the second equation:x = 0.75y
Now substitute x into the first equation:2(0.75y) - 3y = 11.5y - 3y = 1-1.5y = 1y = -1/1.5y = -2/3
Now that we have found the value of y, we can substitute it back into the second equation to find x:x = 0.75(-2/3)x = -1/2
Therefore, the solution to the system of equations is x = -1/2 and y = -2/3.
To solve this system of equations, we can use substitution or elimination method.
Let's use substitution method:
First, isolate x in the second equation:
x = 0.75y
Now substitute x into the first equation:
2(0.75y) - 3y = 1
1.5y - 3y = 1
-1.5y = 1
y = -1/1.5
y = -2/3
Now that we have found the value of y, we can substitute it back into the second equation to find x:
x = 0.75(-2/3)
x = -1/2
Therefore, the solution to the system of equations is x = -1/2 and y = -2/3.