Expanding the equation, we get:
3(x^2 - 2x + 1) - 3x(x - 5) = 23x^2 - 6x + 3 - 3x^2 + 15x = 29x + 3 = 29x = 1x = 2
Therefore, the value of x that solves the equation is 2.
Expanding the equation, we get:
3(x^2 - 2x + 1) - 3x(x - 5) = 2
3x^2 - 6x + 3 - 3x^2 + 15x = 2
9x + 3 = 2
9x = 1
x = 2
Therefore, the value of x that solves the equation is 2.