Корень из ydy=3:
ydy = ∫√y dy = (2/3)(y^(3/2)) = y^(3/2) = 9/y = (9/2)^(2/3y = 27/8
Корень из xdx:
∫√x d(2/3)x^(3/2) + C
Корень из ydy=3:
ydy =
∫√y dy =
(2/3)(y^(3/2)) =
y^(3/2) = 9/
y = (9/2)^(2/3
y = 27/8
Корень из xdx:
∫√x d
(2/3)x^(3/2) + C