To find the solutions to the given equation, we need to set each factor individually to zero.
sinx - 1 = sinx = x = π/2 + 2πn, where n is an integer
2cosx + 1 = cosx = -1/x = 2π/3 + 2πn or x = 4π/3 + 2πn, where n is an integer
tangent(x) ≠ 0 (since it appears in the denominator), therefore, the factor involving tangent can never be 0.
Therefore, the solutions to the given equation arex = π/2 + 2πn, 2π/3 + 2πn, or 4π/3 + 2πn, where n is an integer.
To find the solutions to the given equation, we need to set each factor individually to zero.
sinx - 1 =
sinx =
x = π/2 + 2πn, where n is an integer
2cosx + 1 =
cosx = -1/
x = 2π/3 + 2πn or x = 4π/3 + 2πn, where n is an integer
tangent(x) ≠ 0 (since it appears in the denominator), therefore, the factor involving tangent can never be 0.
Therefore, the solutions to the given equation are
x = π/2 + 2πn, 2π/3 + 2πn, or 4π/3 + 2πn, where n is an integer.