(x^-3 y^4/9)^-2×(3/ x^-2 y^3)^-3

Предыдущий
вопрос Следующий
вопрос

To simplify the expression, we will start by using the power rule which states that for any base raised to an exponent raised to another exponent is equivalent to multiplying the exponents.

First, simplify each term within the parentheses:

(x^-3 y^4/9)^-2 = (1/(x^3 y^4/9))^2 = 1/(x^6 y^8/81) = 81/(x^6 y^8)(3/ x^-2 y^3)^-3 = (3/1 x^2/y^3)^-3 = (3x^2/y^3)^-3 = 3^-3 (x^2)^-3 * (y^3)^3 = 1/(27x^6 y^9)

Now multiply the simplified terms together
81/(x^6 y^8) 1/(27x^6 y^9
= 81/(27x^6 y^8 x^6 y^9
= 3/(x^12 y^17)