Log15 log5 log2(32) = log15(log5(log2(32)))
First, we solve for log2(32):log2(32) = log2(2^5)= 5
Next, we find log5(log2(32)):= log5(5)= 1
Finally, we calculate log15(log5(log2(32))):= log15(1)= 0
Therefore, log15 log5 log2(32) = 0.
Log15 log5 log2(32) = log15(log5(log2(32)))
First, we solve for log2(32):
log2(32) = log2(2^5)
= 5
Next, we find log5(log2(32)):
= log5(5)
= 1
Finally, we calculate log15(log5(log2(32))):
= log15(1)
= 0
Therefore, log15 log5 log2(32) = 0.