Log2(8x-3)-log2 5 =1

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First, we can use the properties of logarithms to combine the two logarithms on the left side of the equation:

log2((8x-3)/5) = 1

Next, we can rewrite the logarithmic equation in exponential form:

2^1 = (8x-3)/5

Simplify:

2 = (8x-3)/5

Multiply both sides by 5:

10 = 8x - 3

Add 3 to both sides:

13 = 8x

Divide by 8:

x = 13/8

Therefore, the solution to the equation log2(8x-3) - log2(5) = 1 is x = 13/8.