|х+7х-4|=4 5х-8|х|+3=0 х|х|+6х-5=0

Предыдущий
вопрос Следующий
вопрос

1) |x+7x-4| = |8x-4| = 4
Solving this equation, we get:
8x-4 = 4 or 8x-4 = -4
8x = 8 or 8x = 0
x = 1 or x = 0

2) 5x-8|x|+3 = 0
This equation does not have real solutions.

3) x|x|+6x-5 = 0
We can rewrite this equation as: |x^2| + 6x - 5 = 0
Using the fact that |x^2| = x^2, we get:
x^2 + 6x - 5 = 0
Solving this quadratic equation, we get:
x^2 + 6x - 5 = (x+1)(x+5) = 0
Therefore, x = -1 or x = -5

So the solutions to the equations are x = 1, x = 0, x = -1, and x = -5.