(х-3)(х-5)=3(х-5) (10Х=12)*4=4Х-2 2Х^6-11Х-40=0 (Х-3)(Х-2)=6(Х-3)

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вопрос

To solve each of these equations, we will take the steps needed for each one:

Now we have the equation x^2 - 8x + 15 = 3x - 15.
Rearranging terms gives us:
x^2 - 11x + 30 = 0

Solve the equation 10x = 12:
Divide by 10 on both sides to isolate x:
x = 12/10 = 6/5 = 1.2

Expand and simplify the expression 4(4x-2) = 4x-2:
4(4x-2) = 16x - 8

Solve the equation 2x^6 - 11x - 40 = 0:
This is a sixth-degree polynomial equation and can be solved through factoring or using numerical methods such as the rational root theorem or graphing the function.

Expand and simplifying the expression (x-3)(x-2) = 6(x-3):
(x-3)(x-2) = x^2 - 2x - 3x + 6 = x^2 - 5x + 6
6(x-3) = 6x - 18

Now we have the equation x^2 - 5x + 6 = 6x - 18.
Rearranging terms gives us:
x^2 - 11x + 24 = 0

These are the solutions for the equations provided.