Arctg(-√3/3)+arctg0-4arctg(-1)

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вопрос

First, simplify the expression using the properties of arctangent:

arctan(-√3/3) = -π/6
arctan(0) = 0
4arctan(-1) = 4*(-π/4) = -π

So, the expression simplifies to:

-π/6 + 0 - (-π) = -π/6 + π = 5π/6

Therefore, the value of the expression is 5π/6.