To solve this equation, we first need to simplify the left side:
(2x)/(x+1) + (3x)/(x-1)
To add these fractions together, we need a common denominator. The common denominator is the product of (x+1) and (x-1), which is (x^2 - 1). We need to rewrite the fractions with this common denominator:
(2x (x-1))/(x+1)(x-1) + (3x (x+1))/(x-1)(x+1)
Expanding the numerators, we get:
(2x^2 - 2x) / (x^2 - 1) + (3x^2 + 3x) / (x^2 - 1)
Now we can combine the fractions:
(2x^2 - 2x + 3x^2 + 3x) / (x^2 - 1)
(5x^2 + x) / (x^2 - 1)
To simplify further, notice that x^2 - 1 can be factored as (x+1)(x-1). So we have:
To solve this equation, we first need to simplify the left side:
(2x)/(x+1) + (3x)/(x-1)
To add these fractions together, we need a common denominator. The common denominator is the product of (x+1) and (x-1), which is (x^2 - 1). We need to rewrite the fractions with this common denominator:
(2x (x-1))/(x+1)(x-1) + (3x (x+1))/(x-1)(x+1)
Expanding the numerators, we get:
(2x^2 - 2x) / (x^2 - 1) + (3x^2 + 3x) / (x^2 - 1)
Now we can combine the fractions:
(2x^2 - 2x + 3x^2 + 3x) / (x^2 - 1)
(5x^2 + x) / (x^2 - 1)
To simplify further, notice that x^2 - 1 can be factored as (x+1)(x-1). So we have:
(5x^2 + x) / (x^2 - 1)
= (5x^2 + x) / ((x+1)(x-1))
This cannot be reduced any further.
So, the original equation is simplified to:
(5x^2 + x) / ((x+1)(x-1)) = (6x)/(x^2-1)